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Section 8.3 Series in a Normed Space

We haven’t talked at all about series so far. That’s because a series is nothing more than a particular kind of sequence.

Definition 8.3.1.

Given a sequence \(v_n \in V\) in a normed space, the series is the sequence
\begin{equation*} S_N=\displaystyle\sum_{n=1}^N v_n\ \ . \end{equation*}
We say that a series converges to \(S\in V\) if \(S_N\to S\text{,}\) and we notate this notion by writing
\begin{equation*} S=\displaystyle\sum_{n=1}^\infty v_n\ \ \ . \end{equation*}

Checkpoint 8.3.2.

Definition 8.3.1 makes clear that every series is a sequence. But it’s also true that every sequence is a series. Prove this by, for a given sequence \((x_n)_{n\in\mathbb{N}}\text{,}\) finding a sequence \((v_n)_{n\in\mathbb{N}}\) with \(\displaystyle x_N=\sum_{n=1}^N v_n\text{.}\)
This proposition records some nice facts about series, each of which is just a basic arithmetic fact and a fact about limits of sequences.

Checkpoint 8.3.6.

Observe that the two series in Corollary 8.3.7 occur in different spaces: one of them is a series of real numbers; the other is a series in a normed space.

Proof.

Notice that the statements here are really statements about series of nonnegative real numbers. So we’ll assume from here on out that each \(a_k\in[0,\infty)\text{.}\)
First, let’s handle the case \(L\lt 1\text{.}\) The hypothesis implies that there is \(K\in\mathbb{N}\) so that \(k\gt K\) guarantees \(a_k\leq \left(\frac{L+1}{2}\right)^k\text{.}\) Now the series
\begin{equation*} \displaystyle \sum_{k=0}^\infty r^k \end{equation*}
converges for any \(r\in [0,1)\text{.}\) So Two Officers and a Drunk, applied with \(0\leq a_k\leq \left(\frac{L+1}{2}\right)^k\) gives the result.
On the other hand, if \(L\gt 1\text{,}\) the hypothesis implies that there are infinitely many \(n\in \mathbb{N}\) with \(a_n\geq \left(\frac{L+1}{2}\right)^n\text{.}\) These form a subsequence \(a_{n_k}\) with \(a_{n_k}\to \infty\text{,}\) which by Proposition 8.3.4 means \(\displaystyle\sum_{k=0}^\infty a_k\) cannot converge.
Here’s how I view the theory of numerical series: the only series whose convergence is really well understood is the geometric series \(\displaystyle\sum_{k=0}^\infty r^k\text{,}\) and all other series we compare to a geometric series using the Root Test. This is, of course, extremely reductive -- but for our purposes, it works well enough.