Applications of Integrals
(Thomas-Finney Section 5.1, page 372)
Problem 31
Find the area of the region enclosed by the curves
and
.
--------------------
First, we'll plot the region of interest. Since the equations are easily solved for y, we'll do that first:
| > | eqn1:=4*x^2+y=4; eqn2:=x^4-y=1; |
| > | y1:=solve(eqn1,y); y2:=solve(eqn2,y); |
And we'll solve for where the curves cross so we know where to plot:
| > | solve({eqn1,eqn2},{x,y}); |
The third thing is complex, so looks like x should go from -1 to 1. We'll go a little farther, just in case:
| > | plot({y1,y2},x=-2..2,color=blue,thickness=2); |
![[Plot]](images/m103ex-5-10_8.gif)
Now we're ready to calculate the area. y1 is on top since it's the parabola that opens down:
| > | area:=int(y1-y2,x=-1..1); |
Section 5.3, page 385 Problem 9
Find the volume of the solid generated by revolving the region bounded by
, for x in
,
,
about the x axis.
--------------------
First we'll graph the region and the solid:
| > | with(plots,tubeplot): |
| > | plot(sqrt(cos(x)),x=0..Pi/2,color=blue,thickness=2); |
![[Plot]](images/m103ex-5-10_14.gif)
| > | tubeplot([x,0,0],x=0..Pi/2,radius=sqrt(cos(x))); |
![[Plot]](images/m103ex-5-10_15.gif)
To calculate the volume, we just integrate
from 0 to
:
| > | volume:=int(Pi*(sqrt(cos(x))^2),x=0..Pi/2); |