\input{ThisWeek.tex}
\newcommand{\classday}{\Tuesday}
\input{../TemplateWeek/InClassWork.tex}
\pgfplotsset{compat=newest}
\input{Exercises.tex}

%\booltrue{teacher}

\section*{Exercise 1}
\Exercise{Review1}

\section*{Exercise 2}
\Exercise{Review2}

\section*{Exercise 3}
\Exercise{Review3}

\section*{Exercise 4}
\Exercise{Review4}

\section*{Exercise 5}
\Exercise{Review5}



\pagebreak

\begin{enumerate}
\item
  \begin{enumerate}[label=(\alph*)]
  \item $\pi$
  \item $0$
  \end{enumerate}
\item $x=20$, $y=15$
\item Only at $x=-\sqrt[7]{\frac{1}{12}}$, $y=4(1/12)^{3/7}$
\item At a rate of 4 km/second
\item The maximum area is obtained when the diameter is $\frac{40}{4+\pi}$ (about $2.8$) and the height is a messy term ($10-\frac{5(2+\pi)}{4+\pi}$) which is about $6.4$.  It's important to check that this really is the maximum rather than the minimum, because if the problem were slightly different (for instance, if there were no floor to the archway), the answer would actually be for the height to be $0$.
\end{enumerate}


\end{document}