Some Problems for August - A few solutions
Some of the following are immediate; most others may take more time
— and require ingenuity and a deeper understanding. They are
intended to be challenging. A complete solution to some may require
ideas we will cover later in the course.
"Elementary" is not the same as "Simple." I hope you will even find
it fun to think about some of these. You may find these interesting
to discuss with others. Remember, the first person you need to
convince is yourself.
General Problems
- Prove that the product of two odd integers is also odd.
- If k > 0 is an integer, is k(k+1)(k+2) always
divisible by 6?
- List these numbers from smallest to largest [but before
computing, make your own intuitive estimate].
2121, 955, 788,
K := an estimate for when
1 + 1/2 + 1/3 + 1/4 + ··· + 1/K > 100.
N := number of seconds since the birth of our universe (about 14
billion years ago),
Solution:
For the first three numbers, one approach uses that their exponents
are all multiples of 11. Thus
2121 = 211×11= 204811 =
[2.048×103]11 = 2.04811 × 1033
955 = 95×11= 5904911 =
[5.9049×104]11 = 5.904911 × 1044
788=78×11 = 576480111 =
[5.764801×106]11 = 5.76480111×
1066
K: Use the integral test estimate to get an upper and
lower bound for the sum. Compare SK with the area under the
curve y = 1/x gives
ln(K+1) < SK < 1+ ln(K)
Since we want ln(K+1) < SK ≥ 100
so we can use any K with ln(K+1) ≥ 100, that is, K +1 ≥
e100 ≈ 2.7×1043
N: 1 year × 365 days/year × 24 hours/day × 60 min/hour × 60 sec/min
= 365×24×60×60 =31,536,000 sec =3.1536 × 107 sec
N ≈ 14 billion years = 14×109 years = 1.4×1010 years
so
N ≈ (1.4×1010)×(3.15360×107) ≈
4.41504×1017 seconds.
This is by far the smallest. Were you surprised?
- If 31025 is divided by 5, what is the remainder?
- If a, b > 0, show that (ab)1/2 ≤ (a + b)/2.
- Is the square root of 7 a rational number? Generalize?
- In Illinois, there are two broods of cicadas. Brood 1 emerges
from the ground every 17 years, Brood 2 every 13 years. They both
appeared in 2024. When is the next year in which they will again both
emerge?
- A Giant Supermarket poster, July 2013
Solve the Problem of the Week:.
Suppose f is a function from positive integers to positive
integers satisfying
f(1)= 1, f(2n) = f(n), and f(2n+1) = f(2n) + 1 for
all positive integers n.
Find the maximum of f(n) when n is greater than or equal to 1 and less
than or equal to 1984.
- Can cos nx be written in the form
a0 + a1cos x + a2cos2x +
...+ ancosnx ?
- Can the function sin x be written as a polynomial (not power
series) in x? How about 2 x?
- Find a formula for
Sn := 12 + 22 +... + n2.
- Does 0.99999... = 1.0000...?
- If c > 0 is a real number, prove there is an integer N so that Nc > 1.
- A function f:R -->R is called even if f(-x)=f(x) for
all x and odd if f(-x)=f(x) for all x.
a). Show that for any f there is an even function, feven
and an odd fnnction, fodd so that
f(x)= feven(x) + fodd(x)
b). Compute this decomposition for f(x):= 1/(1+x), and for
f(x):=p(x)/q(x), where p and q are any polynomials.
c). Show that a polynomial p(x) is even if and only if it contains
only even powers of x.
d). Show that the derivative of a (differentiable) even function is
odd and that the derivative of a (differentiable) odd function is even.
e). Let f(x) be defined by a convergent power series
f(x) := Σ akxk. Show that f is even if
and only if the power series contains only even powers of x.
- (a) Among all triangles inscribed in a fixed circle, show that
equilateral triangles have the largest area.
(b) Among all triangles in the plane with fixed area
A0, show that equilateral triangles have the smallest
perimeter. [Equivalently, if you fix the perimeter, then equilateral
triangles have the largest area.]
(c) Generalize?
Rust Remover:
- Since Math 103 is a prerequisite, you should feel comfortable with
all the material from it. Here are two old Final Exams:
Fall 2007,
Fall 2008.
- Describe the real numbers x that satisfy |x − 2| < 3.
- Sketch the points (x,y) in the plane where |x − y| > 1.
- a). How many real roots does
x4 + x2 − 2x + 2 = 0 have?
b). Find all points (x,y) in the plane that satisfy x2 -
2xy + 5y2 = 0.
- Show that
√(7 + 2√6) − √(7 − 2√6) = 2.
- Solve log9(5 − 3x) = -1/2 for x.
- Let A = (-6,3), B = (2,7), and C be the vertices of a triangle.
Say the altitudes through the vertices A and B intersect at Q = (2,-1).
Find the coordinates of C.
[
The altitude through a vertex of a triangle is a straight line
through the vertex that is perpendicular to the opposite side — or an
extension of the opposite side. Although not needed here, the three
altitudes always intersect in a single point, sometimes called the
orthocenter of the triangle.]
Solution: Let V = Q − A, W = Q − B. Pick
V⊥ and W⊥ perpendicular to V and W,
respectively. Then the sides of the triangle are the lines
X(t) = A + tW⊥, Y(s) = B + sV⊥.
C is the intersection of these lines.
At this point <X(t),V> = <Y(s),V> = <B,V>,
so t = ≤B−A,V>/<W⊥,V>.
Hence C = A + [<B−A,V>/<W⊥,V>]W⊥.
In this problem B−A=(8,4), V=(8,-4), W=(0,-8) so we can let
V⊥=(1,2) and W⊥=(1,0).
Then t = 48/8 = 6 so C = (-6,3) + 6(1,0) = (0,3).